出错信息指明了Timeout异常是在执行connect的时候出现的，因此你要把connect调用也包括到try块中来，像这样：

s = socket.socket(socket.AF_INET,socket.SOCK_STREAM)
try:
s.connect((host,81))
s.send(request)
buf = s.recv(1000)
except timeoutsocket.Timeout:
print 'Timeout!'
else:
print buf

On 5/1/05, . newbie <learnpython at gmail.com> wrote:
> 
> 我的代码大体是这样的：
> import sys
> import socket
> import time
> import timeoutsocket
> timeoutsocket.setDefaultSocketTimeout(2)
> 
> def connect(request):
> host = "192.168.0.1 <http://192.168.0.1>"
> s = socket.socket(socket.AF_INET,socket.SOCK_STREAM)
> s.connect((host,81))
> s.send(request)
> try:
> s.recv(1000)
> except timeoutsocket.Timeout:
> print 'Timeout!'
> else:
> print s.recv(1000)
> 
> a1 = ['a', 'b', 'c']
> a2 = ['a', 'b', 'c']
> for i in a1:
> for j in a2:
> request = i + j
> connect(request)
> 
> 运行之后， File "D:\myprogram\timeoutsocket.py", line 238, in conne
> ct
> raise Timeout("Attempted connect to %s timed out." % str(addr) )
> timeoutsocket.Timeout: Attempted connect to ('192.168.0.1<http://192.168.0.1>', 
> 81) timed out.
> 
> 程序还是退出了，我想即使timeout出现，循环能继续执行，怎么做？
> 我比较愚钝，大家再指点一下
> 多谢
> 在05-5-1，Qiangning Hong<hongqn at gmail.com> 写道：
> > 
> google了一下，你说的是http://www.steffensiebert.de/soft/python/timeoutsocket.py吗？
> >
> > timeoutsocket.py的docstring里有这样的描述：
> >
> > The timeout applies to the socket functions that normally block on
> > execution: read, write, connect, and accept. If any of these
> > operations exceeds the specified timeout, the exception Timeout
> > will be raised.
> >
> > 可以看出，超时时会抛出异常。你只需要用try...except...机制捕获这个异常进行处理就好了。
> >
> > 例如：
> >
> > while keep_going:
> > try:
> > buf = sck.recv(10)
> > except timeoutsocket.Timeout:
> > print 'Timeout!'
> > else:
> > do_something(buf)
> >
> >
> >
> > On 5/1/05, . newbie <learnpython at gmail.com> wrote:
> > >
> > > 我在程序里用了Timothy O'Malley写的timeoutsocket.py的timeout功能，
> > > 在程序开头这样写：
> > > import timeoutsocket
> > > timeoutsocket.setDefaultSocketTimeout(2)
> > >
> > > 超时值设成了两秒。
> > > 超时后，程序就退出了
> > >
> > > 问题是，假如我是一个循环，超时后我想让循环继续，而不是退出，该怎么做？
> > >
> > > 这个问题类似于C里面exit和return一样，我想要的只是它return一个值给我，而不是exit(1)，
> > >
> > > 该怎么解决？
> > >
> > > 多谢
> > >
> > > _______________________________________________
> > > python-chinese list
> > > python-chinese at lists.python.cn
> > > http://python.cn/mailman/listinfo/python-chinese
> > >
> > >
> > >
> >
> >
> >
> > --
> > Qiangning Hong
> > Get Firefox!
> > <http://www.spreadfirefox.com/?q=affiliates&id=67907&t=1
> > >
> >
> 



-- 
Qiangning Hong
Get Firefox! <
http://www.spreadfirefox.com/?q=affiliates&id=67907&t=1>
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问题已经解决了，像下面那样写就可以了：
filePath = unicode(QFileDialog.getOpenFileName(None, "All Files (*)", self))
text = codecs.open(filePath, "r", "mbcs").read().encode("utf-8")
用unicode()函数将getOpenFileName对话框返回的文件名转换为unicode，就可以识别和显示了。
PyXEdit是我写来练手的一个代码编辑器，是基于PyQScintilla的；像eric也是基于PyQScintilla的。

======== 2005-05-01 22:08:20 您在来信中写道： ========

我没有用过PyQT，不过从出错信息来看，我觉得是filePath.ascii()的问题。
这个PyXEdit是个什么东东？



On 5/1/05, Xia Gao <xiaogao at mails.tsinghua.edu.cn> wrote:
大家好！

        我是Python的初学者，今天用PyQT遇到一个问题：当用"打开"对话框打开文件时，如果不是中文文件名，就可以打开；否则会出现以下异常：
Traceback (most recent call last):
  File "F:\Python\PyXEdit\QXEMainWindow.py", line 132, in fileOpen
    self.loadFile (filePath)
  File "F:\Python\PyXEdit\QXEMainWindow.py", line 158, in loadFile
    text = codecs.open(filePath.ascii().encode("mbcs"), "r", "mbcs").read().enco
de("utf-8") 
  File "C:\Python24\lib\codecs.py", line 607, in open
    file = __builtin__.open(filename, mode, buffering)
IOError: [Errno 2] No such file or directory: 'F:/Python/PyXEdit/Test?????.txt'
问题应该是中文文件名不能处理。请大家帮忙想想办法，谢谢！ 

致
礼！


Xia Gao
xiaogao at mails.tsinghua.edu.cn
2005-05-01

_______________________________________________
python-chinese list
python-chinese at lists.python.cn
http://python.cn/mailman/listinfo/python-chinese






-- 
Qiangning Hong
Get Firefox! < http://www.spreadfirefox.com/?q=affiliates&id=67907&t=1>


= = = = = = = = = = = = = = = = = = = = = = 
　　　　　　　　致
礼！

　　　　　　　　　　　　　　Xia Gao
　　　　　　　　　　　　　　xiaogao at mails.tsinghua.edu.cn
　　　　　　　　　　　　　　　2005-05-01