> 
> Leo Jay wrote:
> > 我想生成一个二维的整数数组，并且数组里的每个元素赋初值-1
> > 我现在的写法如下：
> > board = [ [-1 for i in range(10)] for j in range(10) ]
> >
> > 有没有什么简短一点的写法啊？二维数组都这么长，那如果是4维的不是要疯掉了？

  更短的写法：）
 board = [ [-1] * 10 ] * 10
 
-- 
If U can see it, then U can do it
If U just believe it, there's nothing to it
I believe U can fly 
From Jetport at gmail.com
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board = [ [-1] * 10 ] * 10
这种写法是错误的，所有列都是一个对象，改变其中一个元素，另外９个都会变，只能这样写：
board = [[-1]*10 for i in range(10)]

在 05-8-31，Jerry<jetport at gmail.com> 写道：
>  
> > Leo Jay wrote:
> > > 我想生成一个二维的整数数组，并且数组里的每个元素赋初值-1
> > > 我现在的写法如下：
> > > board = [ [-1 for i in range(10)]  for j in range(10) ] 
> > >
> > > 有没有什么简短一点的写法啊？二维数组都这么长，那如果是4维的不是要疯掉了？
>  
>   
>   
> 更短的写法：） 
>   
> board = [ [-1] * 10 ] * 10 
>   
> 
> -- 
> If U can see it, then U can do it
> If U just believe it, there's nothing to it
> I believe U can fly 
> From Jetport at gmail.com
>   
> _______________________________________________
> python-chinese list
> python-chinese at lists.python.cn
> http://python.cn/mailman/listinfo/python-chinese
> 
> 
>

在 05-8-31，Jerry<jetport at gmail.com> 写道：
>  
> > Leo Jay wrote:
> > > 我想生成一个二维的整数数组，并且数组里的每个元素赋初值-1
> > > 我现在的写法如下：
> > > board = [ [-1 for i in range(10)]  for j in range(10) ] 
> > >
> > > 有没有什么简短一点的写法啊？二维数组都这么长，那如果是4维的不是要疯掉了？
>  
>   
>   
> 更短的写法：） 
>   
> board = [ [-1] * 10 ] * 10 
>   

这就是我想说的问题，你改了一个，其它的也都改了。简化一下：

 >>> board = [ [-1] * 2 ] * 2
 >>> board
 [[-1, -1], [-1, -1]]
 >>> board[0][0] = 1
 >>> board
 [[1, -1], [1, -1]]

-- 
I like python! 
My Donews Blog: http://www.donews.net/limodou

> 
> > > Leo Jay wrote:
> > > > 我想生成一个二维的整数数组，并且数组里的每个元素赋初值-1
> > > > 我现在的写法如下：
> > > > board = [ [-1 for i in range(10)] for j in range(10) ]
> > > >
> > > > 有没有什么简短一点的写法啊？二维数组都这么长，那如果是4维的不是要疯掉了？
> >
> >
> >
> > 更短的写法：）
> >
> > board = [ [-1] * 10 ] * 10
> >
> 
> 这就是我想说的问题，你改了一个，其它的也都改了。简化一下：
> 
> >>> board = [ [-1] * 2 ] * 2
> >>> board
> [[-1, -1], [-1, -1]]
> >>> board[0][0] = 1
> >>> board
> [[1, -1], [1, -1]]
> 
>  谢谢 limodou 大哥，我回复的时候还没看到你的回复
的确，python在对象的传递都是引用的
为此，看了python library reference关于的对象的复制,我试着用copy模块完成下面多维函数的构造
 from copy import deepcopy
def multiarray( v,*k):
if len(k) == 0:return v
ret = []
for i in range(k[-1]):
ret.append(deepcopy(v))
return multiarray(ret,*k[:-1])
 
调用如：
x = multiarray(-1,2,3,4,5)
返回4维的initial value 为 -1的数组


-- 
If U can see it, then U can do it
If U just believe it, there's nothing to it
I believe U can fly 
From Jetport at gmail.com
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嗯，我想问一个问题。

不论是简化的写法，还是原来比较复杂的写法。在性能上是否存在差异？




-----Original Message-----
From: python-chinese-bounces at lists.python.cn
[mailto:python-chinese-bounces at lists.python.cn]On Behalf Of limodou
Sent: 2005年8月31日 15:31
To: python-chinese at lists.python.cn
Subject: Re: [python-chinese] 请问，怎么声明一个二维的数组啊？


在 05-8-31，Jerry<jetport at gmail.com> 写道：
>
> > Leo Jay wrote:
> > > 我想生成一个二维的整数数组，并且数组里的每个元素赋初值-1
> > > 我现在的写法如下：
> > > board = [ [-1 for i in range(10)]  for j in range(10) ]
> > >
> > > 有没有什么简短一点的写法啊？二维数组都这么长，那如果是4维的不是要疯掉
了？
>
>
>
> 更短的写法：）
>
> board = [ [-1] * 10 ] * 10
>

这就是我想说的问题，你改了一个，其它的也都改了。简化一下：

 >>> board = [ [-1] * 2 ] * 2
 >>> board
 [[-1, -1], [-1, -1]]
 >>> board[0][0] = 1
 >>> board
 [[1, -1], [1, -1]]

--
I like python!
My Donews Blog: http://www.donews.net/limodou

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你去下 PythonWin的源码，就什么经验都有了。