def fun2():
a+=1
print a
def fun1():
a=1
fun2()
fun1()
我想让a作为fun1的局部变量，但实际运行起来确不行？

a的确是fun1的局部变量，所以和fun2没关系，你要把它传给fun2才行

On 6/21/06, crocodile.liu <crocodile.liu at 163.com> wrote:
>
> def fun2():
> a+=1
> print a
> def fun1():
> a=1
> fun2()
> fun1()
> 我想让a作为fun1的局部变量，但实际运行起来确不行？
>
> _______________________________________________
> python-chinese
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>

xxmplus 写道:
> a的确是fun1的局部变量，所以和fun2没关系，你要把它传给fun2才行
>
> On 6/21/06, crocodile.liu <crocodile.liu at 163.com> wrote:
>>
>> def fun2():
>> a+=1
>> print a
>> def fun1():
>> a=1
>> fun2()
>> fun1()
>> 我想让a作为fun1的局部变量，但实际运行起来确不行？
>>
>> _______________________________________________
>> python-chinese
>> Post: send python-chinese at lists.python.cn
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>> Unsubscribe: send unsubscribe to python-chinese-request at lists.python.cn
>> Detail Info: http://python.cn/mailman/listinfo/python-chinese
>>
> ------------------------------------------------------------------------
>
> _______________________________________________
> python-chinese
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我想在运行fun2后修改a的值

crocodile.liu 写道:
> xxmplus 写道:
>   
>> a的确是fun1的局部变量，所以和fun2没关系，你要把它传给fun2才行
>>
>> On 6/21/06, crocodile.liu <crocodile.liu at 163.com> wrote:
>>     
>>> def fun2():
>>> a+=1
>>> print a
>>> def fun1():
>>> a=1
>>> fun2()
>>> fun1()
>>> 我想让a作为fun1的局部变量，但实际运行起来确不行？
>>>
>>> _______________________________________________
>>> python-chinese
>>> Post: send python-chinese at lists.python.cn
>>> Subscribe: send subscribe to python-chinese-request at lists.python.cn
>>> Unsubscribe: send unsubscribe to python-chinese-request at lists.python.cn
>>> Detail Info: http://python.cn/mailman/listinfo/python-chinese
>>>
>>>       
>> ------------------------------------------------------------------------
>>
>> _______________________________________________
>> python-chinese
>> Post: send python-chinese at lists.python.cn
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>>     
>
>
> _______________________________________________
> python-chinese
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>
>   

什么是函数？函数就是为了隔离数据和行为，局部变量就是应该作为局部变量使用。为什么要挑战如此基本的设计规则？这种想法从根本上违背了代码封装，违反了结构化编程的基本原则。函数唯一的数据传递途径就应该是参数，如果你想要一个函数（不是类方法）使用一个外部的数据，就应该把它通过参数传递进来，不应该有第二个途径――在实际使用中，我们确实有机会用到全局变量，也有很多使用全局变量写出的好代码，但是你这样的想法实在是不应该出现在2006年的代码中。

在06-6-20，crocodile.liu <crocodile.liu at 163.com> 写道：
>
>
> def fun2():
> a+=1
> print a
> def fun1():
> a=1
> fun2()
> fun1()
> 我想让a作为fun1的局部变量，但实际运行起来确不行？
>
> _______________________________________________
> python-chinese
> Post: send python-chinese at lists.python.cn
> Subscribe: send subscribe to python-chinese-request at lists.python.cn
> Unsubscribe: send unsubscribe to  python-chinese-request at lists.python.cn
> Detail Info: http://python.cn/mailman/listinfo/python-chinese
>



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刘鑫
March.Liu
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crocodile.liu wrote:

>def fun2():
>a+=1
>print a
>def fun1():
>a=1
>fun2()
>fun1()
>我想让a作为fun1的局部变量，但实际运行起来确不行？
>
>_______________________________________________
>python-chinese
>Post: send python-chinese at lists.python.cn
>Subscribe: send subscribe to python-chinese-request at lists.python.cn
>Unsubscribe: send unsubscribe to  python-chinese-request at lists.python.cn
>Detail Info: http://python.cn/mailman/listinfo/python-chinese
>
>  
>
你这不是捣乱么? ;-)
局部变量嘛, 顾名思义, 就是只能在某函数/方法的某次运行内有效的变量. 如果
你想让大家共享, 得用全局变量啊.