def A(func):
def new_func(*args, **argkw):
result = func(*args, **argkw) #调用原函数继续进行处理
if result:
#做一些额外的工作
return new_result
else:
return result
return new_func
@A
def f(args):pass

args argkw如何就是f的args?如何传进去的

----- Original Message ----- 
From: "Brightman" <mr.brightman at gmail.com>
To: <python-chinese at lists.python.cn>; <python-cn at googlegroups.com>
Sent: Monday, May 21, 2007 5:09 PM
Subject: [python-chinese] 请教decorate的机制


> def A(func):
> def new_func(*args, **argkw):
> result = func(*args, **argkw) #调用原函数继续进行处理
> if result:
> #做一些额外的工作
> return new_result
> else:
> return result
> return new_func
> @A
> def f(args):pass
> 
> args argkw如何就是f的args?如何传进去的

不是很理解你说的，我估计是写错了吧，应该也是*args, **argkw,
@A
def f(*args,**argkw): pass

Python没有魔力可以把args变成*args, **argkw，它只能老老实实的按你的定义去传参数。

vcc
_

vcc 写道:
> ----- Original Message ----- 
> From: "Brightman" <mr.brightman在gmail.com>
> To: <python-chinese在lists.python.cn>; <python-cn在googlegroups.com>
> Sent: Monday, May 21, 2007 5:09 PM
> Subject: [python-chinese] 请教decorate的机制
>
>
>   
>> def A(func):
>> def new_func(*args, **argkw):
>> result = func(*args, **argkw) #调用原函数继续进行处理
>> if result:
>> #做一些额外的工作
>> return new_result
>> else:
>> return result
>> return new_func
>> @A
>> def f(args):pass
>>
>> args argkw如何就是f的args?如何传进去的
>>     
呵呵，表述的不清楚。问题：new_func如何得到def f(args)的参数，实际上new_func(*args,**argkw),args argkw就是f函数的参数,想知道它是如何实现的

def A(func):
    def new_func(*args,**argkw)
       print "calling %s with args %s, %s" % (func.__name__, args, argkw)
    return new_func
@A
def f1(user,age):
    pass

> 不是很理解你说的，我估计是写错了吧，应该也是*args, **argkw,
> @A
> def f(*args,**argkw): pass
>
> Python没有魔力可以把args变成*args, **argkw，它只能老老实实的按你的定义去传参数。
>
> vcc
> _
> _______________________________________________
> python-chinese
> Post: send python-chinese在lists.python.cn
> Subscribe: send subscribe to python-chinese-request在lists.python.cn
> Unsubscribe: send unsubscribe to  python-chinese-request在lists.python.cn
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http://wiki.woodpecker.org.cn/moin/ObpLovelyPython/LpyQLearn-4-func#decorator

On 5/21/07, Brightman <mr.brightman at gmail.com> wrote:
>
> def A(func):
> def new_func(*args, **argkw):
> result = func(*args, **argkw) #调用原函数继续进行处理
> if result:
> #做一些额外的工作
> return new_result
> else:
> return result
> return new_func
> @A
> def f(args):pass
>
> args argkw如何就是f的args?如何传进去的
> _______________________________________________
> python-chinese
> Post: send python-chinese at lists.python.cn
> Subscribe: send subscribe to python-chinese-request at lists.python.cn
> Unsubscribe: send unsubscribe to  python-chinese-request at lists.python.cn
> Detail Info: http://python.cn/mailman/listinfo/python-chinese




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